ERCISE 19
LEVEL-1
Find the area of a triangle whose sides are respectively 150 cm, 120 cm and 200.
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Answer:
semiperimeter of triangle (s)=a+b+c whole by 2
area of triangle=√s(s-a)(s-b)(s-c)
where
s=semiperimeter
a;b;c are sides
s=150+120+200/2=470/2=235
area of triangle=√235(235-150)(235-120)(235-200)
=√235(85)(115)(35)=√80399375
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