erefore, the width of the river is
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EXERCISE 9.1
1. A circus artist is climbing a 20 m long rope, which is
tightly stretched and tied from the top of a vertical
pole to the ground. Find the height of the pole, if
the angle made by the rope with the ground level is
30° (see Fig. 9.11).
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Gɪᴠᴇɴ:
- A circus artist is climbing a 20m long rope.
- Angle made by the rope with ground level is 30°.
ᴛᴏ ғɪɴᴅ:
- The height of the pole.
- Distance of rope from base of the pole.
ᴀɴsᴡᴇʀ:
For figure refer to attachment:
Given that a circus artist is climbing a 20m long rope and angle made by the rope with ground level is 30°.
If we consider a right ∆ ABC right angled at B , then
- The length of rope will be hypotenuse.
- Distance of rope from pole will be base.
- Height of pole will be perpendicular.
As here base and hypotenuse are given we must use cosine.
→In ∆ ABC :
⇒cos30° = AB/AC.
⇒√3/2 = AB/ 30m.
⇒AB = 30 × √3/2 m.
⇒AB = 15√3m.
Hence the distance of rope From base of pole is 15√3m
___________________________________
As here perpendicular and hypotenuse are given we must use cosine.
→ Again in ∆ ABC :
⇒ sin30° = BC/AC.
⇒1/√2 = BC/30m.
⇒BC = 30 × 1/√2m.
⇒BC = √2×√2×15/√2 m.
⇒BC = 15√2m.
Hence the height of the pole is 15√2m.
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