Question

Eric and Jane work for Omega Airlines and their job is to clean aircrafts after landing to make it ready for the next set of passengers to board. It takes Eric 4 hours to clean an aircraft himself. It takes Jane 6 hours to clean the same aircraft by herself.

How long will it take them if they start working on cleaning the aircraft together and neither of them stops until the aircraft is completely clean?​

Answer 1

Answer:

sorry I don't know sorry

Answer 2

Solution :-

Basic Method :-

→ Time taken by Eric to clean an aircraft himself = 4 hours .

so,

→ Per hour work of eric = (1/4)

similarly,

→ Time taken by Jane to clean an aircraft himself = 6 hours .

so,

→ Per hour work of eric = (1/6)

then,

→ Per hour work of both = (1/4) + (1/6) = (3 + 2)/12 = (5/12)

therefore,

→ Time taken by them to clean an aircraft together = (12/5) = 2(2/5) hours = 2 hours , 24 minutes .

LCM Method :-

→ LCM of 4 and 6 = 12 units = Let total work done .

so,

→ Efficiency of Eric = Total work / Time taken = 12/4 = 3 units / hour .

and,

→ Efficiency of Jane = Total work / Time taken = 12/6 = 2 units / hour .

then,

→ Efficiency of them together = (3 + 2) = 5 units / hour .

therefore,

→ Time taken by them to clean an aircraft together = (12/5) = 2(2/5) hours = 2 hours , 24 minutes .

Learn more :-

Giri does 2/5 piece of work in 10 days. Ankit does 5/9 of the remaining work in 15 days and Gaurav finishes remaining wo...

https://brainly.in/question/21025557

Shivam alone can do a work in 12 days and Maanik alone can do it in, 15 days. Both started the work together and after w...

https://brainly.in/question/14687371