Math, asked by Niranj9236, 1 year ago

Eric made two investments: Investment Q QQ has a value of $ 5 0 0 $500dollar sign, 500 at the end of the first year and increases by $ 4 5 $45dollar sign, 45 per year. Investment R RR has a value of $ 4 0 0 $400dollar sign, 400 at the end of the first year and increases by 1 0 % 10%10, percent per year. Eric checks the value of his investments once a year, at the end of the year. What is the first year in which Eric sees that investment R RR's value exceeded investment Q QQ's value?

Answers

Answered by amitnrw
3

Given: Eric made two investments: Q has a value of  $500 & R has a value of  $400

To find :  first year in which Eric sees that investment R  value exceeded investment Q value?

Solution:

Let say after n years  Eric sees that investment R value exceeded investment Q value

Q Value  = 500 $

Q value after n Years = 500 + 45n

R value = 400 $

R value after n year = 400 ( 1 + 10/100)ⁿ

400 ( 1 + 10/100)ⁿ  > 500 + 45n

= 400 ( 1.1)ⁿ  > 500 + 45n

n = 8

400 ( 1.1)⁸  = 857

500 + 45* 8 = 860

n = 9

400 ( 1.1)⁹  = 943

500 + 45* 9 = 905

=> after 9 Years   Eric sees that investment R value exceeded investment Q value

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Answered by neadhnouv
1

Answer:

10. It's on khan academy.

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