Question

erification : Here - +
EXERCISE 34
1. Solve the following pair of linear equations by the and the substitution
method:
(1) r+y=5 and 21-3y=4
(i) 3r4y= 10 and 21-2y = 2
mm) 3r-5y-4 = 0 and 9r = 2y + 7
=- and -23
(iv)​

Answer 1

Answer:

1. r+y =5 put value for r as 1 so

1+y=5

so y=5-1=4

2. 21-2y=2

-2y=2-21

-2y=-19

y=19/2 no negative symbol it's being cancelled