Erode 10 M wide surrounds a circular Park whose perimeter is 352 M find the area of the road
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Circumference of the park=352m
=>2πr=352m
=>
=>
=>
r=8×7
=>r=56m
therefore total radius along with the
=>road=56+10=66m
Area of the park=πr²
=>22/7×56×56
=>68992/7
=>9856m²
Area of park along with the road=πr²
=>22/7×66×66
=>95832/7
=>13690.2857
Area of the road=13690.2857-9856
=>
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Answered by
5
park perimeter=2πr = 352 or r = 352/2π = 56M
park radius = 56 M then it's area = πr²= π(56)²= 3136π
road width =10 M
now, with road total radius = 56+10=66M
total area= πr² = π(66)²=4356π
area of road = total area - park area
4356π - 3136π = 1220π now put π value
1220×3.1428 = 3834.2 M²
park radius = 56 M then it's area = πr²= π(56)²= 3136π
road width =10 M
now, with road total radius = 56+10=66M
total area= πr² = π(66)²=4356π
area of road = total area - park area
4356π - 3136π = 1220π now put π value
1220×3.1428 = 3834.2 M²
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