Math, asked by gunjan951985, 1 year ago

Erode 10 M wide surrounds a circular Park whose perimeter is 352 M find the area of the road


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Answers

Answered by Victory1234
12
 \huge{Heya \: Mate}

Here's your answer friend!!

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Circumference of the park=352m

=>2πr=352m

=>2× \frac{22}{7} ×r=352m

=> \frac{44}{7} ×r=352m

=>r= \frac{352}{1} × \frac{7}{44}
r=8×7

=>r=56m

therefore total radius along with the

=>road=56+10=66m

Area of the park=πr²

=>22/7×56×56

=>68992/7

=>9856m²

Area of park along with the road=πr²

=>22/7×66×66

=>95832/7

=>13690.2857

Area of the road=13690.2857-9856

=> \boxed{\boxed{ = 3834.2857 {m}^{2} }}
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Hope \: It \: Helps
Answered by s7388
5
park perimeter=2πr = 352 or r = 352/2π = 56M
park radius = 56 M then it's area = πr²= π(56)²= 3136π
road width =10 M
now, with road total radius = 56+10=66M
total area= πr² = π(66)²=4356π
area of road = total area - park area
4356π - 3136π = 1220π now put π value
1220×3.1428 = 3834.2 M²
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