Math, asked by rithikraghav6757, 10 months ago

Error in measurement of radius of sphere is 1% tje error in volume

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Answered by Anonymous

0

Volume = 4πR³/3

ΔV/V × 100 = 3(∆R / R) × 100

= 3 × (1/100) × 100

= 3

∴ Percentage error in volume is 3%

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