Question

Error in measuring radius of a sphere is 2% then the error in volume of sphere is

Answer 1

Step-by-step explanation:

error in measuring radius of the sphere is 2% =>∆r. Volume of the sphere =>

$\frac{4}{3}\pi {r}^{3}$

So error in volume of sphere is 3 times ∆r =>6% . Hope it helps you.