Physics, asked by Madisynstl5691, 11 months ago

Error   in   radius   is   3%,   what   is   error   in   volume   of   spher

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Answered by swati1212
0

Answer:

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Answered by Anonymous
0

Answer:

So, a 3 % error range [−0.03r,0.03r] , in r would be propagated in V(r) as;

V(r±0.03r)=43π(r±0.03r)3

and the relative error interval (range) of V(r) would be;

V(r±0.03r)−V(r)V(r)=[−0.081327,0.092727]

The calculation given by relative rates of change would give;

dV(r)V(r)=3drr

So, the relative rate of change of V would be three times that of r . However, these are NOT errors propagated. They are relative rates of change.

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