Question

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the value of m for which the equation
(m + 4)x2 + (m + 1)x + 1 = 0 has real and
equal roots.​

Answer 1

Answer:

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Step-by-step explanation:

Given that the roots of the quadratic equation (4+m)x

2

+(m+1)x+1=0 are equal.

∴ the discriminant b

2

−4ac will be equal to 0.

Here a=4+m,b=m+1,c=1

∴b

2

−4ac=(m+1)

2

−4(4+m)(1)=0

⇒(m+1)

2

−4(4+m)=0

⇒m

2

+2m+1−16−4m=0

⇒m

2

−2m−15=0

⇒(m−5)(m+3)=0

⇒m=5or−3