Question

es. 2. a) Solve the following LPP graphically
Maximize Z = 6x;+7x2
Subject to the constraints 2x+3x2 < 12, 2x;+x2 5-8 and xı, x220​

Answer 1

Answer:

Given objective function is Z=x+2y

We have to minimize Z on constraints

2x+y≥3

x+2y≥6

x≥0,y≥0

After plotting the inequalities we got the feasible region as shown in the image

Now there are two corner points (0,3) and (6,0) lying on same line x+2y=6

Value at corner points are :

Corner Points  Value of Z=x+2y

(0,3)  6 (minimum)

(6,0)  6 (minimum)

Since, feasible region is unbounded. So, 6 may or may not be minimum value.

Now to check if 6 is minimum or not, we have to draw Z<6⇒x+2y<6

Since this region doesn't have any common region with feasible region.  

So, 6 is the minimum value of Z.

Step-by-step explanation: