Question

es if x= 3 + Square root 8, then the value of x ² + 1/x Square
is.
(A) 32
(B) 34
(C) 26
(D) 12
Please don't spam
Answer for class 9
​

Answer 1

$\huge{\bigstar}{ \green{ \mathfrak{ \underline{ \underline{Question}}}}}{\bigstar}$

□☆□☆□☆□☆□☆□☆□☆□☆□☆□☆□☆

$if \ x= 3 + \sqrt8,\ then \ the\ value\ of\ x^2 + \displaystyle\frac{1}{x^2}$

□☆□☆□☆□☆□☆□☆□☆□☆□☆□☆□☆

──────────────────────

$\huge{\bigstar}{ \green{ \mathfrak{ \underline{ \underline{Answer}}}}}{\bigstar}$

$\boxed{\red{\bold{Given:}}}$

$x = 3 + \sqrt8$

$\displaystyle \frac{1}{x} = \frac{1}{3 + \sqrt8}$

$\displaystyle \frac{1}{x} = \frac{1}{3 + \sqrt8} \times \frac{3-\sqrt8}{3-\sqrt8}$

$\displaystyle \frac{1}{x} = \frac{3- \sqrt8}{3^2 -(\sqrt8)^2}$

$\displaystyle \frac{1}{x} = \frac{3- \sqrt8}{9 -8}$

$\displaystyle \frac{1}{x} = 3-\sqrt8$

$\boxed{\red{\bold{Now :}}}$

$x^2 + \displaystyle \frac{1}{x^2} = (3+\sqrt8)^2 + (3-\sqrt8)^2$

$x^2 + \displaystyle \frac{1}{x^2} = 9 + 8 + 2× 3× \sqrt8 + 9 + 8 -2 × 3 × \sqrt8$

$x^2 + \displaystyle \frac{1}{x^2} = 34$

──────────────────────

Answer 2

(B)34

please flow me

I think this answer will help you