Question

es2: Form a quadratic polynomial whose zero's are 2 and -4​

Answer 1

Step-by-step explanation:

the answer for this question

Answer 2

Answer:

x^2+2x-8=0

Step-by-step explanation:

let 2be the alpha and -4 be the beta

we know that,

sum of roots = alpha + beta

-b/c = 2+(-4)

-b/c = 2-4

-b/c = -2

products of roots = alpha*beta

c/a = 2*(-4)

c/a = -8

here we see that -b = -2

b=2

a=1

c= -8

quadratic equation is in the form :-

ax^2+bx+c=0

So the equation is

x^2+2x+(-8)=0

x^2+2x-8=0