Physics, asked by narayanaraopkl4610, 1 year ago

Escape velocity from earthis 11.2 km/s the escape velocity from planet of mass as that of earth bur radius 1/4

Answers

Answered by RJ12345

2

Vc= √ GM/R
Vc1 = 11.2 km/sec
M1= M2
R2=R1/4
vc2= √GM/R/4=√4GM/R
= 2√GM/R
= 2*11.2
= 22.4Km/sec

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