Escape velocity of a planet is 20km/s.find the orbital velocity of smallest possible orbit
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Escape velocity = √2 × orbital velocity
20 = √2 × orbital velocity
orbital velocity = 20/√2 = 10√2 =14.142 km/s
20 = √2 × orbital velocity
orbital velocity = 20/√2 = 10√2 =14.142 km/s
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Answer:
The R value (radius of orbit) is the earth's radius plus the height above the earth - in this case, 6.77 x 106 m. Answer: The orbital velocity of the smallest possible orbit is 7.91 km/s.Jan 5, 2020
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