Question

escape velocity of earth is 11.2km/s. the orbit no of H atom in which speed of electron is about 19.54 times the escape velocity is
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Answer 1

Answer:

Explanation:

Escape velocity of the planet is the velocity thrown at which the object escapes the gravitational potential of the planet.

1/2mv^2esc = GMm/R

v=√2GM/R

v'/v= √M'/M X R/R'= √100/1 X 1/4 = 5

V' = 56.0 km /s