Escape velocity on the surface of earth is 11.2.if the mass of earth increase to twice it's value and the radius of the earth becomes half the escape velocity?
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Explanation:
Escape velocity , v
e
=
R
e
2GM
e
=11.2km/s
For R
′
=
2
R
e
M
′
=2M
e
v
e
′
=
2
R
e
2G(2M
e
)
=2v
e
=22.4km/s
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