Question

Escape velocity on the surface of the earth is 11.2 kms. If the
mass of the earth increases to twice its value and the radius of
the earth becomes half the escape velocity is
a. 5.6 kms-1
b. 11.2kms-1
C. 22.4 kms-1
d. 33.6 kms-1​

Answer 1

Answer:

Option C. 22.4 km/s

Explaination:

Since , Ve = √MG/R

If R' = R/2

and M' = 2M

Than ,

Ve' = √4MG/R

= 2× Ve = 22.4km/s