Question

Esha,babu and chitra work in a handicraft factory. Esha alone takes 10hrs to complete a single product but babu and chitra working together takes 4hrs for the completion of the same product. If all of them worked together and completed 14 products then how many hours they have worked ?

Answer 1

Answer:

They have worked for 40 hours

Step-by-step explanation:

Since Esha taked 10 hours to complete a product

Therefore, work done by Esha in 1 hour = 1/10

Let work done by Babu in 1 hour = 1/x

Work done by Chitra in 1 hour = 1/y

Then, work done Babu and Chitra in 4 hours = $4(\frac{1}{x}+\frac{1}{y})$

According to the question

$4(\frac{1}{x}+\frac{1}{y})=1$

$\implies \frac{1}{x}+\frac{1}{y}=\frac{1}{4}$

If all of them are working together, then in 1 hour, the product completed

$=\frac{1}{10}+\frac{1}{x}+\frac{1}{y}$

$=\frac{1}{10}+\frac{1}{4}$

Let us assume they worked for n hours

Then the product made in n hours = 14

or, $n(\frac{1}{10}+\frac{1}{4})=14$

$\implies n(\frac{2+5}{20})=14$

$\implies n(\frac{7}{20})=14$

$\implies n=40$

Therefore, they together worked for 40 hours to make 14 products.