Math, asked by golurajsingh7th, 5 months ago

Esme sa koi sa v solution bana sakte hai.​

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Answered by Anonymous
1

Answer:

ques 5:

5 raised to the power of 4

7 with cube and lastly 9 with square or insted of 9, 3 can be written with power of 4

5^4×7^3×9^2

or

5^4×7^3×3^4

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Answered by Anonymous
5

Step-by-step explanation:

7)let 2m be 16

so m=16/2=8

so m²+1=8²+1=64+1=65

and m²-1=8²-1=64-1=63

so the pythagorean triplets are 16,65,63

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