Essay on we all experience a situation which posses a challenge to us
Answers
This was a evening which was so hard to believe, sad to expect.
One day, I and my friend Mounir, were going to some place cycling.
We were going great. The conversation build up as we moved forward.My friend is so intelligent and caring towards me.
Suddenly,he asked me a intelligent question that "Consider a boy, girl are friends, if something danger happens to both of them, that one has to challenge with life to save the other. Will they keep their life in danger, for saving the other. "
I thought he was asking generally, so I replied "Yes" with a sense of doubt in my mind. he told, we are friends, if something happens to you, if I have to give up my life. I will guarantely take up the situation.
We were happy and moved further. As we finished our trip that day.We two went to our respective houses. As Daily, after school, we again took our bicycles, started our ride with great enthusiasm.
We went into a highway. The rest is sad and danger. A car driver who was driving after consuming Alcohol, was about to hit me.I was so scared and nervous, about my situation there. My friend Mounir has taken the challenge and pushed me aside,kept him self in danger. he risked his life for my sake. Accident was to happen, and it happened, but not to me, but to him.
I fell from my bicycle and got minor injuries on knees and elbows.But what happened to Mounir was something serious. The car went on to hit him, leaving blood in his head.Luckily, God saved him, I fell unconscious,And when the time I woke up, I was in hospital. I noticed Mounir in the bed beside me. I got to near him and asked that why you risked yourselves for me. he told this is true friendship. I was not able to understand anything that time. I kept crying for an hour. After I was fully conscious, I saw Mounir with a bandage to his head.
By God's grace she recoved fast. Now too when I think about him,I remember this incident. This is the true friendship that has to be with friends.
To Prove:
tanθ−secθ+1
tanθ+secθ−1
=
cosθ
1+sinθ
Solution:
L.H.S =
tanθ−secθ+1
tanθ+secθ−1
We can write, sec
2
θ−tan
2
θ=1
=
tanθ−secθ+1
tanθ+secθ−(sec
2
θ−tan
2
θ)
=
tanθ−secθ+1
tanθ+secθ−(secθ−tanθ)(secθ+tanθ)
=
tanθ−secθ+1
(tanθ+secθ){1−(secθ−tanθ)}
=
tanθ−secθ+1
(tanθ+secθ){1−secθ+tanθ}
=tanθ+secθ
=
cosθ
sinθ
+
cosθ
1
=
cosθ
1+sinθ
= R.H.S
since L.H.S = R.H.S
tanθ−secθ+1
tanθ+secθ−1
=
cosθ
1+sinθ
Hence Proved.