ESSAY TYPE
2. The ratio of the length and breadth of a
rectangular field is 3:2 and its area is 11094
sq m. What will be the cost of fencing the
field at the rate of 2.50 per metre?
TE
Answers
GIVEN
The ratio of the length and breadth of a
rectangular field is 3:2 and its area is 11094 sq m.
TO FIND
What will be the cost of fencing the
field at the rate of 2.50 per metre?
SOLUTION
- Area of rectangle = 11094 m²
✒ According to the given condition
✞ Let the length be 3x and breadth
be 2x
Area of rectangle = 11094
➡ length × breadth = 11094
➡ 3x*2x = 11094
➡ 6x² = 11094
➡ x² = 11094/6
➡ x² = 1849
➡ x = √1849
➡ x = ± 43
★ Length and breadth never in negative
Hence,
Length = 3x = 3 × 43 = 129 m
Breadth = 2x = 2 × 43 = 86 m
_____________________
✒Now, Perimeter of rectangle
➡ 2(Length + breadth)
➡ 2(129 + 86)
➡ 2 × 215 = 430 m
Cost of fencing 1m field = Rs.2.50
Cost of fencing 430m field
= Rs.2.50*430 = Rs.1075
_____________________
✧ Given:-
- Ratio of length and breadth:- 3:2
- Area of rectangular field:- 11094m²
✧ To find:-
- Cost of fencing field at the rate of 2.50 per metre?
✧ Solution:-
- Area:- 11094m²
- Ratio of length and breadth:- 3:2
Let's the length be 3x and breadth be 2x.
- Area of rectangle = Length × Breadth
- 11094 = (3x) × (2x)
- 11094 = 6x²
- = x²
- 1849 = x²
Taking sqrt. both side:-
- =
★ Putting value of x in 3x and 2x :-
- 3x = 3 × 43 = 129m
Hence, length of rectangular field is 129m.
- 2x = 2 × 43 = 86m
Hence, breadth of rectangular field is 86m.
★ Now, we should find the perimeter of rectangular field:-
Perimeter of rectangle :- 2( length + breadth)
- 2( 129 + 86)
- 2 × 215
✶ Given that, cost of fencing 1m field :- 2.50 Rs.
✶ Cost of fencing 430m field :- 2.50 × 430