establish an equation to find out pH value of .1 M acetic acid solution
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[CH3COOH] is given 0.1 M
CH3COOH has a Ka of 1.8×10^-5
=> Ka = [H+][CH3COO-]/[CH3COOH]
=>[H+] ²=Ka×[CH3COOH]
=>[H+] = √(1.8×10^-5)(0.1)
=>[H+] = 0.0037947331922021
=>pH = -log(0.0037947331922021)
=>pH = 2.42081875395237
CH3COOH has a Ka of 1.8×10^-5
=> Ka = [H+][CH3COO-]/[CH3COOH]
=>[H+] ²=Ka×[CH3COOH]
=>[H+] = √(1.8×10^-5)(0.1)
=>[H+] = 0.0037947331922021
=>pH = -log(0.0037947331922021)
=>pH = 2.42081875395237
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