Establish an expression to prove F=ma..
Answers
Answered by
5
force α change in momentum
initial momentum = mu
final momentum = mv
the rate of change of momentum
f α mv -mu
f. α [ m(v-u) /t
we know that
a=v-u/t
f. α ma
f = kma
mass = 1kg, a= 1ms^2 , f=1N then, let the k=1
f= ma(proved)
initial momentum = mu
final momentum = mv
the rate of change of momentum
f α mv -mu
f. α [ m(v-u) /t
we know that
a=v-u/t
f. α ma
f = kma
mass = 1kg, a= 1ms^2 , f=1N then, let the k=1
f= ma(proved)
Answered by
2
f=mxa is the thing that we have to derive
f is proportional to p/t
m(v-u) /t. [p=m(v-u) ]
f is proportional to mxa. [a = v-u/t]
f= k x m x a
f=1 x m x a. [let k = 1]
f= m xa hence proved
f is proportional to p/t
m(v-u) /t. [p=m(v-u) ]
f is proportional to mxa. [a = v-u/t]
f= k x m x a
f=1 x m x a. [let k = 1]
f= m xa hence proved
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