Question

Establish expression for orbital velocity and time period of a satellite

Answer 1

Answer: T=2pi under root R/g

Explanation:

In equilibrium, the centripetal force is provided by the gravitational force of the earth, here;

mv^2 / (R+h) = GMm/ (R+h) ^2

Therefore ,

orbital velocity = under root of the

GM /R+h

= under root of the gR^2 /R+h

= R under root of g /R+h

-> time period of satellite = d /v

= 2pi r/v

= 2pi (R+h) / under root of GM /R+h

Therefore,

T= 2pi under root (R+h) ^3 /GM

T= 2pi under root (R+h) ^3 /gR^2

-> If h<<R,

T = 2pi under root R^3 /gR^2

T = 2pi under root R /g

Hope this might be helpful to you.

Answer 2

Answer:this is the right answer..... Mark it as brainleast.....

Explanation: