Establish relation between Kp and Kc.
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Kp And Kc
Kp And Kc are the equilibrium constant of an ideal gaseous mixture. Kp is equilibrium constant used when equilibrium concentrations are expressed in atmospheric pressure and Kc is equilibrium constant used when equilibrium concentrations are expressed in molarity.
For many general chemical reactions aA + bB ⇋ cC + dD
Where a mole of reactant A
b mole of reactant B
c mole of product C
d mole of product D
Consider an example
2A(g)+B(g) ⇋ 2C(g) All in the gas phase.
The Kp is given by-
Kp=P2CP2APB ———(1)
PV = nRT
On rearranging we get-
P=nVRT
Substituting these in equation (1)
⇒Kp=[C]2(RT)2[A]2(RT)2[B](RT) ⇒Kp=[C]2[A]2[B]×(RT)2(RT)2(RT)
On canceling like terms and substituting Kc=[C]2[A]2[B] we get-
⇒Kp=KcRT
hope this will help
Kp And Kc are the equilibrium constant of an ideal gaseous mixture. Kp is equilibrium constant used when equilibrium concentrations are expressed in atmospheric pressure and Kc is equilibrium constant used when equilibrium concentrations are expressed in molarity.
For many general chemical reactions aA + bB ⇋ cC + dD
Where a mole of reactant A
b mole of reactant B
c mole of product C
d mole of product D
Consider an example
2A(g)+B(g) ⇋ 2C(g) All in the gas phase.
The Kp is given by-
Kp=P2CP2APB ———(1)
PV = nRT
On rearranging we get-
P=nVRT
Substituting these in equation (1)
⇒Kp=[C]2(RT)2[A]2(RT)2[B](RT) ⇒Kp=[C]2[A]2[B]×(RT)2(RT)2(RT)
On canceling like terms and substituting Kc=[C]2[A]2[B] we get-
⇒Kp=KcRT
hope this will help
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Answer:
Then Kp=Kc. Case-2: If the change in the number of moles of gas molecules is positive, i.e., if Δng > 0 then, Kp>Kc.
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