Question

Establish the relationship between density and pressure of an ideal gas. ???​

Answer 1

Answer:

Force, F=10N

Mass, m=5Kg

Force,

F=ma

a=2m/s

2

Work done, W=F.ds

In first second, displacement,

s=

2

1

at

2

s=

2

1

×2×1

s=1m

So, work done,W=10×1=10J

In second second, s=

2

1

×2×4=4m

So, the displacement is , 4−1=3m

Hence, work done in 2 second is,

W=10×3

W=30J

Explanation:

sorry I no the correct answer

Answer 2

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HERE IS UR ANSWER

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$density = \frac{pressure}{temp.}$

Density is directly proportional to pressure and indirectly proportional to temperature. As pressure increases, with temperature constant, density increases. Conversely when temperature increases, with pressure constant, density decreases.