Establish the relationship between kWh and Joules. (b) An electric refrigerator rated 400 W operates 8 hour per day . What is the cost of the energy to operate it for 30 days at Rs 3.00 per kW h?
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(a) One kilowatt-hour is equivalent to the energy of 1,000 joules used for 3,600 seconds or 3.6 million Joules. In equation form: 1 kWh = 3.6 million J. So if your building uses 5000 kWh each day, your building is consuming the same amount of energy that would be required to lift 18 billion cans of soda per day.
(b) Cost of the energy to operate refrigerator at a rate of Rs 3.00 per kWh = 96 x 3.00 = Rs 288.00.
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