Question

establish the relationship between zeroes and coefficients of p(x)=x²+2x-15​

Answer 1

Step-by-step explanation:

According to the question-

$p(x) = {x}^{2} + 2x - 15 \\ let \\ \alpha \: \: and \: \beta \: are \: the \: roots \: of \: this \: equation \\ \\ sum \: of \: roots \: = \frac{ - co \: efficient \: of \: x}{co \: efficient \: of \: {x}^{2} } \\ \\ \alpha \: + \beta \implies \: - \frac{2}{1} = 2 \\ \\ product \: of \: roots \: = \frac{constant \: term}{co \: effcient \: of \: {x}^{2} } \\ \\ \alpha \beta \: = \frac{ - 15}{1} = 15$

Hope it helps you.

Answer 2

Step-by-step explanation:

x^2 +2x-15

x^2 +5x+3x-15

x(x-5)+3(x-5)

x+3=3

×-5=5 these are the zeros....

hope it helps you.........

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