Physics, asked by lishaandhakad, 7 months ago

Establishing the relation between the loss in weight of a solid when fully immersed in a) Tap water b) Strongly salty water with the weight of water displaced by it by taking at least two different solids.

Answers

Answered by kanak9a152020
27

Theory

Fluids: Gases and liquids flow and are thus called fluids.

Buoyancy: The upward force exerted by fluids on any body is called the buoyant force and this phenomenon is known as buoyancy.

Thrust: The force acting on a body perpendicular to its surface is called thrust. S.I. unit is Newton.

Pressure: The thrust per unit area is called pressure.

Pressure =\frac { Thrust }{ Area }

S.I. Unit =\frac { N }{ { m }^{ 2 } } or Nm-2. This unit (Nm-2)is also called Pascal,

.’. 1 Pascal (Pa) = 1 Nm-2

Weight of a body = Mass x acceleration due to gravity

W = mg

When a body is immersed in water or liquid, the body displaces some liquid.

The volume of liquid displaced = total volume of the solid.

The mass of liquid displaced can be measured as:

Mass of liquid displaced = Volume x Density

M = V x D

Weight of liquid displaced = Volume x Density x g (acceleration due to gravity)

W = V x D x g

The body loses some weight when immersed in fluid, it can be found as follows:

Weight of the body in air = W1

Weight of the body when immersed in liquid = W2

Hence loss in weight = W2 -W1

How much will be this upward force/buoyant force depends on the density of liquid in which it is immersed. The upthrust is more by denser liquids.

Archimedes’ Principle: When a body is immersed fully or partially in a fluid, it experiences an upward force that is equal to the weight of the fluid displaced by it.

Materials Required

A spring balance, a metal bob, a cotton thread, an overflow can, a glass beaker, tap water, salty water, an iron stand.

Procedure

A. Find the zero error and least count of spring balance:

Take an iron stand and suspend a spring balance to it.

Study the spring balance, its scale and its least count.

Record your observations. If any error, record it as ‘x’ gf.

B. Find the weight of solid metal bob in air:

Take a metal bob, tie thread to it and suspend on the hook of the spring balance.

Record the weight of the metal bob in air. Let this weight be Wr

C. Find the weight of the metal bob immersed in tap water and record the apparent loss in weight

Take an overflow can, fill it with water such that its water level touches the spout of the overflow can.

Keep an overflow can under the spring balance such that the metal bob gets fully immersed in the water of

the overflow can.

Keep a beaker whose weight P1 is recorded, at the mouth of the spout of overflow can.

As soon as the metal bob is suspended in water the weight on spring balance scale is recorded. This loss in weight is due to buoyancy (W2).

Collect the water that has overflown in a beaker till the last drop that comes out of the spout.

Weigh the beaker with water (P2).

Calculate the weight of the displaced water (P2-P1).

Calculate the loss in weight of the metal bob when immersed in water.

NCERT Class 9 Science Lab Manual - Archimedes’ Principle-1

D. Find the weight of metal bob immersed in salty water and record the apparent loss in weight.

Prepare salty water by taking a 500 mL beaker and adding 300 mL of water in it and dissolving common salt till the saturated solution is obtained.

Take the same metal bob and repeat the steps from 1 to 8 as given in procedure ‘C’

Tabulate your observations.

Observations and Calculations

Zero error in spring balance = (x) = 0 gf.

Least count of the spring balance = 2 gf.

Density of water = 1 g/cm3

Weight of empty beaker P1= 100 gf.

NCERT Class 9 Science Lab Manual - Archimedes’ Principle-2

NCERT Class 9 Science Lab Manual - Archimedes’ Principle-3

Conclusion

Hence it is proved that the weight of the water displaced by the metal bob is approximately equal to the apparent loss of weight of the metal bob in water. Archimedes’ principle is verified.

The weight of water displaced by a given solid when immersed fully in strongly salty water is more than the weight of the water displaced when fully immersed in tap water.

Precautions

Carefully study the spring balance used for the experiment.

Fill the overflow can above the mark of the spout, allow extra water to overflow through the spout without disturbing it. Use this overflow can for the experiment.

Do not allow the suspended solid mass i.e. metal bob/stone to touch the base and sides of the overflow beaker.

VIVA VOCE

Answered by probrainsme101
5

Concept:

We use the archimedes principle which says that the bouyant force is equal to the weight of the fluid displaced.

Given :

We have two types of liquid in which the object is dipped.

Find:

Relation between the loss in weight in the two liquids.

Solution:

We know that the loss in weight is due to the buoyant force, which is given by

                                          F_{Buoyant}=V_{solid}D_{liquid}g

Hence we see that the Buoyant force is proportional to the Density of the liquid.

Since the density of Strongly Salty water is more than that of tap water.

It is easy to conclude that the weight loss in Strongly Salty Water is more than that of tap water.

#SPJ3

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