Question

estimate surface temp. of star that emits an intense light of frequency 4.8×10×14​

Answer 1

Answer:

Using weins law ie λ=B/T

The answer will be 2*10^11

Answer 2

The radiation intensity of the star is 1.9447791× $10^{-20}$

Given:

The intense light of frequency is 4.8 ×10×14

To Find:

The radiation intensity of the star using the intense of frequency

Solution:

According to Wein's displacement law,

λmaxT = b

T = $\frac{b}{λmax }$

= $\frac{2898mew m k}{4.8(10)(14)}$

= 0.00043035(10)^-7

According to Stefan Boltzmann law,

Radiation Intensity ,

R = σT4

R = ( 5.67×10 −8Wm−2K−4)(0.00043035(10)^-7)^4

= 1.9447791×$10^{-20}$

Hence, the radiation intensity is  1.9447791×$10^{-20}$