Chemistry, asked by vikasrathour9775, 10 days ago

Estimate the boiling point of Br2(l) ( H = 30.9 kJ; S = 93.0 J/K). Br2(l) Br2(g)

Answers

Answered by Sampurnakarpha
1

Answer:

The temperature at which the process be spontaneous is calculated as follows

delta G = delta H -T delta S

let delta G be =0

therefore delta H- T delta s =0

therefore T= delta H/ delta S

convert 31 Kj to J = 31 x1000= 31000 j/mol

T=31000j/mol /93 j/mol.k =333.33K

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Explanation:

Answered by DeenaMathew
0

The boiling point of Br2(l) is 332.25K.

Given:

Br2(l) H = 30.9 kJ; S = 93.0 J/K. Br2(l)-----> Br2(g).

To Find:

The boiling point of Br2(l).

Solution:

To find the boiling point of Br2(l) we will follow the following steps:

As we know,

The formula relation between temperature and entropy is

∆G = ∆H - T∆S

Here,

∆G is Gibbs free energy and is equal to zero because boiling is an equilibrium reaction.

For equilibrium reaction ∆G = 0

So,

0 = ∆H - T∆S

∆H = T∆S

T =  \frac{ ∆H}{∆S}  =  \frac{30.9 \times 1000}{93}  = 332.25k

Henceforth, the boiling point of Br2(l) is 332.25K.

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