Estimate the force a person must exert on a string attached to a 0.150 kg ball to make the ball revolve in a horizontal circle of radius 0.60 m. The ball makes 2 revolutions per second. Neglect the mass of the string.
Answers
Answer:
Given
The mass of the ball:
m
=
0.150
k
g
The length of the string:
l
=
0.600
m
The frequency of rotation of the...
See full answer below.
Answer:
95 m/s²
Explanation:
We know that Acceleration = Velocity^2/Radius.
Where Velocity = displacement/ time.
In this case, the displacement is circular displacement. Circular displacement is nothing but the distance you covered along the circle, which is nothing but circumference .Circumference of a circle is 2*Pi*r.
Ball takes 2 complete revolutions. Hence twice around a circle, therefore is the total displacement 2* (2*Pi*r) in total time 1 sec.
Substitution in velocity formula we get, velocity = 4*Pi*r. Substitute velocity back in acceleration formula, you'll get 16*pi^2*r. Plug in the values and it roughly calculates to 95 m/s^2.