Question

Estimate the number of electrons in 10 g of water and
find charge on them. ​

Answer 1

$\underline{ \boxed{ \bold{ \mathfrak{ \huge{ \purple{Answer}}}}}}$

Given :

mass of water = 10 g

To Find :

no. of electrons and charge...

Calculation :

$\dag\rm \: mole = \frac{weight}{molecular \: weight} \\ \\ \therefore \rm \: n = \frac{10}{18} = 0.555 \\ \\ \dag \rm \: no.of \: electrons = n \times n{a} \times 8 \\ \\ \therefore \rm \: electrons = 0.555 \times 6.022 \times {10}^{23} \times 8 \\ \\ \therefore \: \underline{ \boxed{ \bold{ \rm{ \purple{no. \: of \: electron = 2.67 \times {10}^{24} }}}}} \\ \\ \dag \rm \: charge = no. \: of \: electron \times 1.6 \times {10}^{ - 19} \\ \\ \therefore \rm \: charge = 2.67 \times {10}^{24} \times 1.6 \times {10}^{ - 19} \\ \\ \therefore \: \underline{\boxed{ \bold{ \rm{ \orange{charge = 4.27 \times {10}^{5} \: c}}}}}$