Physics, asked by Abhisrivastava3167, 1 year ago

Estimate the number of electrons in 100 g of water. How much is the total negative charge on these electrons ?

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Answered by kaddsy
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What is the estimated total number of electrons present in 100g of water? How much is the total negative charge carried by these electrons?

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6 ANSWERS



Alok Mandal, Dy. MANAGER at Coal India Limited (2010-present)

Answered Sep 5, 2017

1 mole of water = 1x2+16 = 18 gram of water

So, 100 g of water means= 100/18 moles of water

Now, 1 molecule of water contains 1x8 electron of Oxygen and 2x1 electron of Hydrogen= 10 electron per molecule.

So total number of electron in 100 gram water =total molecule in 100 gram water x number of electron in each molecule= (100/18)×10 moles

= 55.555 moles of electron= 55.555x6.022x10^23 numbers of electron.

Charge on 1 mole electron = 1 Farad

So total charge of these electron= 55.555 Farad

= 55.555× 96485.34 coulombs

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