Estimate the number of electrons in 100 g of water. How much is the total negative charge on these electrons ?
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What is the estimated total number of electrons present in 100g of water? How much is the total negative charge carried by these electrons?
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Alok Mandal, Dy. MANAGER at Coal India Limited (2010-present)
Answered Sep 5, 2017
1 mole of water = 1x2+16 = 18 gram of water
So, 100 g of water means= 100/18 moles of water
Now, 1 molecule of water contains 1x8 electron of Oxygen and 2x1 electron of Hydrogen= 10 electron per molecule.
So total number of electron in 100 gram water =total molecule in 100 gram water x number of electron in each molecule= (100/18)×10 moles
= 55.555 moles of electron= 55.555x6.022x10^23 numbers of electron.
Charge on 1 mole electron = 1 Farad
So total charge of these electron= 55.555 Farad
= 55.555× 96485.34 coulombs
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6 ANSWERS

Alok Mandal, Dy. MANAGER at Coal India Limited (2010-present)
Answered Sep 5, 2017
1 mole of water = 1x2+16 = 18 gram of water
So, 100 g of water means= 100/18 moles of water
Now, 1 molecule of water contains 1x8 electron of Oxygen and 2x1 electron of Hydrogen= 10 electron per molecule.
So total number of electron in 100 gram water =total molecule in 100 gram water x number of electron in each molecule= (100/18)×10 moles
= 55.555 moles of electron= 55.555x6.022x10^23 numbers of electron.
Charge on 1 mole electron = 1 Farad
So total charge of these electron= 55.555 Farad
= 55.555× 96485.34 coulombs
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