Question

estimate the number of images produced if a tiny object is kept in between two plan included at 35°, 36°,40°,45°​

Answer 1

Given :

Tiny object is kept between twi plane mirror inclined at

1. 35°
2. 36°
3. 40°
4. 45°

To find :

Number of image formed in each caes

SOLUTION :

First of all we will find "n" { refer to attachment }

1) 35°

$\sf \implies \:n \: = \: \dfrac{360}{35}\\\\\sf \implies\:n\:=\:10.28$

Here n is even so,

➝ Number of images formed = n - 1

➝ Number of images formed = 10.28 - 1

➝ Number of images formed = 9.28

➝ Number of images formed ≈ 9

_______________________________________________

2) 36°

$\sf \implies \: n \: = \: \dfrac{360}{36}\sf\implies\:n\:=\:10$

Here n , is even so

➝ Number of images formed = n - 1

➝ Number of images formed = 10 - 1

➝ Number of images formed = 9

_______________________________________________

3) 40°

$\sf \implies \: n\: = \: \dfrac{360}{40} \\ \\ \: \sf \implies \: n \: = \: 9$

Here n is odd ,

(a) If symmetrical

➝ Number of images formed = n - 1

➝ Number of images formed = 9 - 1

➝ Number of images formed = 8

(b) If asymmetrical

➝ Number of images formed = n

➝ Number of images formed = 9

_______________________________________________

4) 45°

$\sf \implies \:n \: = \: \dfrac{360}{45} - 1 \\ \\ \sf \implies \: n \: = \: \: 8$

Here n is even

➝ Number of images formed = n - 1

➝ Number of images formed = 8 - 1

➝ Number of images formed = 7

_____________________________________________

ANSWER :

Number of images formed

1. 9
2. 9
3. 8 or 9 { based on object }
4. 7