Estimate the total no of electrons present in 100g of water. how much is the total negative charge carried by these electrons? avagadros number=6.02×10^23 and molecular mass of water is 18
Answers
Answered by
8
H y friend hope this will help you...
________________________
In 1 molecule of H2O. 2 atoms of hydrogen.
&1 atom of oxygen present
in hydrogen has 1 electron
& oxygen has 8 electron
in 1 molecule 9 elecron present
oxygen has has
100 g water=100/18=55.55mole of water
in 1 mole 6.02×10^23 molecule presents
Hence total no. of electrons
=6.02×10^23 *9*55 electrons
_____________________
________________________
In 1 molecule of H2O. 2 atoms of hydrogen.
&1 atom of oxygen present
in hydrogen has 1 electron
& oxygen has 8 electron
in 1 molecule 9 elecron present
oxygen has has
100 g water=100/18=55.55mole of water
in 1 mole 6.02×10^23 molecule presents
Hence total no. of electrons
=6.02×10^23 *9*55 electrons
_____________________
Similar questions