Estimate the value of the following to the nearest to one decimal place.
(i)√90
(ii) √150
(iii) √600
(iv)√1000
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Answer:
1)√90 =9.52
2)√150=12.23
3)√600=24.5
Step-by-step explanation:
We know that
√90 ≈ 9.4868
To approximate 9.4868 to one decimal place we have to look on second digit after point.
"If it is greater then 5 then we will add 1 in first digit after point."
In our case it is 8 which is greater then 5 so we add 1 in 4 to get 5
And
√90 ≈ 9.5
Now
√150 ≈ 12.2474
Here second digit after point is 4 which is less then 5 so we will not add 1
And so
√150 ≈ 12.2
Now
√600 ≈ 24.4948
Here second digit after point is 9 which is greater then 5.So we add 1 in 4 to get 5.
And
√600 ≈ 24.5
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