Question

Ethane-1,2-diol reacts with sodium then what happened?

Answer 1

Explanation:

Ethane-1,2-diols or ethylene glycol reacts slowly with sodium metal at 50°C temperature and forms monosodium glycolate.

$HO-CH_2-CH_2-OH+Na\overset{50^oC}\rightarrow HO-CH_2-CH_2-O^-Na^+$

On higher temperature it forms disodium glycolate.

$HO-CH_2-CH_2-O^-Na^++Na\overset{\Delta }\rightarrow Na^+O^--CH_2-CH_2-O^-Na^+$

Answer 2

Explanation :

As there are two condition for this reaction :

When the ethane-1,2-diols reacts with the sodium metal at low temperature then it forms monosodium glycolate.

The chemical reaction will be :

$HO-CH_2-CH_2-OH+Na\overset{\text{Low temp.}}\rightarrow HO-CH_2-CH_2-O^-Na^+$

When the ethane-1,2-diols reacts with the sodium metal at high temperature then it forms disodium glycolate.

The chemical reaction will be :

$HO-CH_2-CH_2-O^-Na^++Na\overset{\text{High temp.}}\rightarrow Na^+O^--CH_2-CH_2-O^-Na^+$