Chemistry, asked by adnanhussain6564, 1 year ago

Ethanoic acid on heating with ammonia forms compound A which on treatment with bromine and sodium hydroxide gives compound B. Compound B on treatment with NaNO₂/dil. HCl gives compound C. The compounds A, B and C respectively are
(a) ethanamide, methanamine, methanol
(b) propanamide, ethanamine, ethanol
(c) N-ethylpropanamide, methaneisonitrile, methanamine
(d) ethanamine, bromoethane, ethanedia-zonium chloride
(e) methanamine, ethanamide, methanol

Answers

Answered by Anonymous
0
 <b>
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→ [B]


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Answered by Anonymous
0

Here is your answer ⤵⤵⤵

(b) propanamide, ethanamine, ethanol

HOPE IT HELPS YOU !!!

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