Ethanoic acid reacts with sodium hydrogen carbonate to produce a salt X and a gas Y. Identify X and Y and write their chemical names. With the help of a labelled diagram describe an activity to confirm that the gas Y is correctly identified by you. Also write the chemical equation of the reaction involved.
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X - CH3COOH SODIUM ETHONOATE
Y - CO2 CARBONDIOXIDE
CH3COOH + NaHCO3 -> CH3COONa +H2O +CO3
to check the presence of gas y take a candle near it if burning candle blow of it shows us that co2 is present
Y - CO2 CARBONDIOXIDE
CH3COOH + NaHCO3 -> CH3COONa +H2O +CO3
to check the presence of gas y take a candle near it if burning candle blow of it shows us that co2 is present
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The reaction of ethanoic acid with sodium hydrogen carbonate
- Generally, a salt, carbon dioxide gas and water is formed as product when ethanoic acid reacts with hydrogen carbonate.
- Accordingly the reaction between Ethanoic acid () reacts with sodium hydrogen carbonate () and yields products with chemical name:
X - Salt - Sodium Acetate
Y - Gas - Carbon dioxide
- The chemical equation involved in the reaction is as follows:
Activity to confirm gas Y
- Take a boiling test tube. In it add a pinch of sodium hydrogen carbonate salt and few ml of ethanoic acid.
- As the chemical reacts fumes of gas starts to liberate.
- Pass the liberate gas into another test tube containing lime water.
- If the lime water turns milky the gas is carbon dioxide, if not it is not carbon dioxide.
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