Chemistry, asked by InnocentBachiNo1, 1 year ago

Ethanoic acid reacts with sodium hydrogen carbonate to produce a salt X and a gas Y. Identify X and Y and write their chemical names. With the help of a labelled diagram describe an activity to confirm that the gas Y is correctly identified by you. Also write the chemical equation of the reaction involved.


atharv33: hii

Answers

Answered by johnysingh
32
X - CH3COOH SODIUM ETHONOATE
Y - CO2 CARBONDIOXIDE
CH3COOH + NaHCO3 -> CH3COONa +H2O +CO3


to check the presence of gas y take a candle near it if burning candle blow of it shows us that co2 is present
Attachments:

InnocentBachiNo1: Diagram?
johnysingh: want diagram?
Answered by zumba12
2

The reaction of ethanoic acid with sodium hydrogen carbonate

  • Generally, a salt, carbon dioxide gas and water is formed as product when ethanoic acid reacts with hydrogen carbonate.
  • Accordingly the reaction between Ethanoic acid (CH_3COOH) reacts with sodium hydrogen carbonate (NaHCO_3) and yields products with chemical name:

X - Salt - Sodium Acetate

Y - Gas - Carbon dioxide

  • The chemical equation involved in the reaction is as follows:

CH_3COOH + NaHCO_3 \rightarrow CH_3COONa + CO_2+H_2O

Activity to confirm gas Y

  • Take a boiling test tube. In it add a pinch of sodium hydrogen carbonate salt and few ml of ethanoic acid.
  • As the chemical reacts fumes of gas starts to liberate.
  • Pass the liberate gas into another test tube containing lime water.
  • If the lime water turns milky the gas is carbon dioxide, if not it is not carbon dioxide.

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