Question

Ethyl acetate is formed by the reaction between ethanol and acetic acid and the equilibrium is represented as: CH₃COOC₂H (l) + C₂H₅OH (l) ⇆ CH₃COOC₂H₅ (l) + H₂O (l) At 293 K, if one starts with 1.00 mol of acetic acid and 0.18 mol of ethanol, there is 0.171 mol of ethyl acetate in the final equilibrium mixture. Calculate the equilibrium constant.

Answer 1

The reaction quotient here Qc= [CH3COOC2H5] [ H2O] / [CH3COOH] [C2H5OH].

By taking the volume of the reaction mixture as v, the equilibrium value will be 0.009/V M., and the equilibrium constant Kc value will be approximately 3.92.

The final reaction quotients Qc value will be 0.204.

So these are the values of both the reaction quotients and the equilibrium constant.