Chemistry, asked by arpansarkar0208, 8 months ago

ethyl acetoacetate reacts with CH3COCH2Cl in presence of NaOH what is the product & mechanism​

Answers

Answered by deepikavim
0

Explanation:

Ethyl acetate when reacts with one mole of methyl magnesium iodiole then the following reaction takes place.

Ethyl acetoacelate is the  ethyl ether of acetoacetic acid.It is used for the production of dyes,inks perfumersec.Alsoethyl aceto acetate is subjected to ketoenol tautomerism.Also ethyl acetate is producedby treatment of diketone with ethanol.

In this reaction,one of the carbonyl  group is replaced by the methyl group of grignard's reagent.

Similar questions