Question

Ethyl bromide+Ethanolio KOH---------?

Answer 1

Heya....

Here's your answer....

When ethyl bromide reacts with aqueous KOH, it undergoes hydrolysis. This occurs through the SN 2 mechanics since the substrate is a primary carbon. The OH group from KOH substitutes the Br group from ethyl bromide. The by product is KBr.

When ethyl bromide reacts with alcoholic KOH, it undergoes beta elimination . The lone pair on O in OH attracts the hydrogen on the beta carbon( the carbon next to the carbon which has the bromide group) and the potasssium cation attracts the bromide group. The product is ethene and the by products are water and KBr.

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Answer 2

Here,CH3CH2Br is Ethyl bromide and KOH is Ethanolio where as CH3CH2OH is Ethyl alcohol and KBr is potassium bromide