Chemistry, asked by jaideep23, 1 year ago

ethyl iodide undergoes SN2 reaction faster than ethyl bromide

Answers

Answered by shubham0040

3

due to higher living order of I as compared to F

jaideep23: Kindly go through the question again.

shubham0040: I>Br>Cl>F

Answered by ReRepeater

0

Explanation:

Basicity decreases with increase in size
Iodine is a better leaving group

Thus ethyl iodide undergoes SN2 reaction faster than ethyl bromide

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