Eu meelt.
12. Four girls, A, B, C and D. share a box of chocolates among themselves. A takes 1/4 of the
chocolates, B takes of the remainder and C takes of the left-overs. What fraction of the
chocolates does D have ?
Answers
Answer:
I don't know
Step-by-step explanation:
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Let us assume that initially A had a chocolates, B had b chocolates, C had c chocolates and D had d chocolates.
Given: a=b+80a=b+80
We need to find: c−d
so , 2a/3 = 34(b+a3)=45(c+b4+a12)=d+15(c+b4+a12)
So now take this one at a time.
2a3=34(b+a3)2a3=34(b+a3)
But you know that a = b + 80. So substitute that into this equation.
2b+1603=34(b+b+803)2b+1603=34(b+b+803)
Simplifying this we get:
3b+a4=4c5+b5+a153b+a4=4c5+b5+a15
Substituting a = 80 and b = 100 in this, we get c = 110
Now solve for the last part of the equation:
45(c+b4+a12)=d+15(c+b4+a12)45(c+b4+a12)=d+15(c+b4+a12)
Taking everything except d to the left hand side we get:
35(c+b4+a12=d35(c+b4+a12=d
Now substituting values of a, b and c into the equation as 180, 100 and 110 respectively we get the value of d as:
d=90d=90
Thus c−d=110−90=20.c−d=110−90=20.
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