Euclid algorithms of 27,37
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HOLA
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27 < 37
37 = 27 × 1 + 10
27 = 10 × 2 + 7
10 = 7 × 1 + 3
7 = 3 × 2 + 1
3 = 1 × 3 + 0
HCF ( 27 , 37 ) = 1
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HOPE U UNDERSTAND ❤❤❤
==================
27 < 37
37 = 27 × 1 + 10
27 = 10 × 2 + 7
10 = 7 × 1 + 3
7 = 3 × 2 + 1
3 = 1 × 3 + 0
HCF ( 27 , 37 ) = 1
=========================
HOPE U UNDERSTAND ❤❤❤
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