euclid division algorithm to prove square of positive integer equal to 3m
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Let b=3
a=bq +r
a=3q+r
Possibility of r =0,1,2
1st case:
When r=0
a^2=(3q+0)^2
a^2=9q
a^2=3*3q
Let 3q =m
a^2=3m
2nd case :
When r =1
a^2=(3q+1)^2
a^2=(9q^2+1+2*3q*1)
a^2=(9q^2+1+6q)
a^2=(9q^2+6q)+1
a^2=3(3q^2+2q)+1
Let (3q^2+2q)=m
a^2=3m+1
Hey mate I hope this will help
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