Euclid's Division Lemma says a = bq + r , where
please prove it
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Answered by
2
hey mate....
lema is a proven statement which is used to prove another statement .
so there is no need to prove this statement .
we can write it simply as:
dividend=divisor x quotient + remainder
taking value and you will get your answer ..
let a= 5 and b=11
then q=2 and r=1
here r less than q .
hope this will help you
lema is a proven statement which is used to prove another statement .
so there is no need to prove this statement .
we can write it simply as:
dividend=divisor x quotient + remainder
taking value and you will get your answer ..
let a= 5 and b=11
then q=2 and r=1
here r less than q .
hope this will help you
Anonymous:
I'm not asking you to prove lemma . just prove r is greater than or equal to 0 and r is less than b
Answered by
2
let a=9
and b=2
on dividing 9by 2
we get 9=2*4+1
i.e,a=bq+r
where a is dividend
b is divisor ,q is quotient and r is remainder but 0=r or 0<r and r<b
and b=2
on dividing 9by 2
we get 9=2*4+1
i.e,a=bq+r
where a is dividend
b is divisor ,q is quotient and r is remainder but 0=r or 0<r and r<b
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