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In Figure-8, a square OPQR is inscribed in a quadrant OA
If the radius of circle is 6/2 cm, find the area of the shaded region.
cribed in a quadrant OAQB of a circle.
Figure-8
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In Figure-8, a square OPQR is inscribed in a quadrant OA
Consider the attached figure while going through the following steps.
Given,
The radius of circle is 6/2 cm
A square OPQR is inscribed in a quadrant OAQB of circle
Area of shaded portion = Area of quadrant - Area of square
OQ = OA = OB = 6/2 cm
In Δ OQR,
OQ² = OR ² + QR²
as we have, (OP = PQ = QR = RO) sides of a square
⇒ OQ² = OR ² + OR² = 2OR²
(6/2)² = 2 OR²
OR = (6/2) √2
OR = 3/√2 cm
Therefore, the side of a square = a = 3/√2 cm
Area of quadrant OAQB = πr²/4
= 22/7 × (6/2)² × 1/4
= 7.07 cm²
Area of square OPQR = a²
= OR²
= (3/√2)²
= 9/2 = 4.5 cm²
Area of shaded portion = 7.07 - 4.5 = 2.57 cm²
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